A) from any source.
B) from any species of bacteria.
C) from the same species of bacteria.
D) only through plasmids.
E) from any source AND only through plasmids.
Correct Answer
verified
Multiple Choice
A) upstream from the gene in question.
B) downstream from the gene in question.
C) within the gene in question.
D) randomly in the genome.
E) in an intron.
Correct Answer
verified
Multiple Choice
A) The dark-light will activate the photorepair systems that can break thymine dimers induced by UV light.
B) The light-it's important to keep on producing the thymine dimers by keeping the plate exposed to light as much as possible.
C) Alternating light and dark every hour to increase the chances that thymine dimers will form, but prevent photorepair systems from correcting them as they are formed.
D) It doesn't matter-human cells don't have the enzymes needed for photorepair of thymine dimers.
E) Alternating light and dark every 24 hours to increase the chances that thymine dimers will form.
Correct Answer
verified
Multiple Choice
A) alkyl groups of the nucleobase.
B) nucleobase sequence.
C) number of binding sites on the nucleobase.
D) hydrogen bonding properties of the nucleobase.
E) nucleobases.
Correct Answer
verified
Multiple Choice
A) conjugation.
B) transformation.
C) induced mutation.
D) vertical gene transfer.
E) transduction.
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) an F plasmid.
B) a Y chromosome.
C) diploid chromosomes.
D) an SOS response.
E) an F plasmid AND diploid chromosomes.
Correct Answer
verified
Multiple Choice
A) a bacterial plasmid promoter that was similar to plant promoters.
B) an R plasmid in plant cells.
C) incorporation of the bacterial chromosome into the plant.
D) incorporation of the plant chromosome into the bacteria.
E) a bacterial plasmid promoter that was similar to plant terminators.
Correct Answer
verified
Multiple Choice
A) Nothing. It's highly likely that two separate virus particles were carrying each gene, and that they coinfected the new target cell at the same time. This could mean the two original genes might not even be from the same original host cell!
B) It's highly likely that the two genes are located next to each other in the host cell chromosome. Since transduction results from a packaging error or an excision error that occurs during the infection cycle of the bacteriophage, the genes must lie close to each other to be transduced into a new cell simultaneously.
C) They must be within five gene lengths of each other, but not necessarily immediately adjacent. If they were immediately adjacent, the transposons that facilitate the transfer of genetic information between the two cells wouldn't be able to "jump" into them.
D) It doesn't mean anything. Transduction relies on the ability of a cell to take up foreign DNA. It's possible here that the cell has simply taken up two separate bits of DNA at the same time from the surrounding environment.
E) It's highly likely that one gene was on the chromosome but the other was actually on a plasmid; if those two elements are in one cell, genes can be transferred simultaneously.
Correct Answer
verified
Multiple Choice
A) The bacteria make restriction enzymes that degrade the virus genome.
B) The bacterial host DNA is protected from restriction enzyme degradation by phosphorylation.
C) The bacterial host DNA is protected from restriction enzyme degradation by methylation.
D) If the phage DNA was methylated, it would be protected from restriction enzyme degradation.
E) The statements are ALL False.
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) sequestered in a lysosome.
B) turned into RNA.
C) methylated.
D) made into double-stranded RNA.
E) phosphorylated.
Correct Answer
verified
Multiple Choice
A) cause mutations to occur.
B) may act as alkylating mutagens.
C) provide an environment in which preexisting mutants survive.
D) increase the rate of spontaneous mutation.
E) destroy all mutant bacteria.
Correct Answer
verified
Multiple Choice
A) penicillin.
B) heat.
C) ground-up rat liver.
D) reverse transcriptase.
E) penicillin AND heat.
Correct Answer
verified
Multiple Choice
A) Proofreading by DNA polymerase, glycosylase enzyme activities, excision repair, SOS repair
B) SOS repair, excision repair, glycosylase enzyme activities, proofreading by DNA polymerase
C) SOS repair, proofreading by DNA polymerase, glycosylase enzyme activities, excision repair
D) Glycosylase enzyme activities, SOS repair, proofreading by DNA polymerase, excision repair
E) Proofreading by DNA polymerase, SOS repair, glycosylase enzyme activities, excision repair
Correct Answer
verified
Multiple Choice
A) UV light.
B) SOS repair.
C) frame shift mutations.
D) genetic recombination.
E) antibiotic resistance.
Correct Answer
verified
Multiple Choice
A) direct selection.
B) replica plating.
C) penicillin enrichment.
D) individual transfer.
E) mutant reversion.
Correct Answer
verified
Multiple Choice
A) involve polyploid chromosomes AND allow populations to be measured.
B) involve antibiotic resistance AND allow populations to be measured.
C) allow populations to be measured AND use an indirect method for measurement.
D) involve haploid chromosomes AND involve antibiotic resistance.
E) use an indirect method for measurement AND involve antibiotic resistance.
Correct Answer
verified
Multiple Choice
A) only in prokaryotes.
B) only in eukaryotes.
C) in both eukaryotes and prokaryotes.
D) in neither eukaryotes nor prokaryotes.
E) None of the answer choices is correct.
Correct Answer
verified
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